How to find x and y intercepts for the equation 2x+3y-15=0?
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The x-intercept has a y-value of 0 and the y-intercept has an x-value of 0. Therefore, you can find the x and y intercepts by substituting 0 in for each variable...
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The equation of a straight line in intercept-intercept form is x/a+y/b = 1 where a is the x-intercept and b is the y-intercept.
Convert the standard form of the equation of the line into the intercept-intercept form.
2x+3y-15=0
Add 15 to both the sides
2x+3y= 15
Divide both sides by 15
`(2x)/15 + (3y)/15 = 1`
`x/(15/2) + y/(15/3) = 1`
`x/7.5 + y/5 = 1`
The x-intercept of the line is 7.5 and the y-intercept is 5
To determine x axis intercept of the given line, we'll have to set y = 0.
2x + 3*0 - 15 = 0
2x - 15 = 0
x = 15/2
The x axis intercepting point is (15/2 ; 0).
To determine y axis intercept of the given line, we'll have to set x = 0.
2*0 + 3y - 15 = 0
3y - 15 = 0
3y = 15
y = 15/3
y = 5
The y axis intercepting point is (0 ; 5).
Therefore, the x and y axis intercepts are: (15/2 ; 0) and (0 ; 5).
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