Find the value of x for the equation 8*2^3x = 4^(x-1).

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We have to solve 8*2^3x = 4^(x-1) for x.

8*2^3x = 4^(x-1)

=> 2^3*2^3x = 2^(2x - 2)

=> 2^(3 + 3x) = 2^(2x - 2)

As the base are equal we can equate the exponent

=> 3+ 3x = 2x - 2

=> 3x - 2x = -2 - 3

=> x = -5

Therefore x = -5

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Given the equation:

8*2^3x = 4^(x-1)

We need to find x value.

First we need to simplify the bases.

We know that 8 = 2^3  and 4 = 2^2

==> (2^3)*(2^3x) = 2^2^(x-1)

Now we know that x^a * x^b = x^(a+b)

Also, we know that x^a^b = x^(ab)

==> 2^(3x+3) = 2^(2x-2)

Now that the bases equal, then the powers are equal too.

==> 3x +3 = 2x -2

We will combine like terms.

==> x = -5

 

 

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