How to find the x-intercepts and y-intercepts this parabola: Y= x^2-4
The x-intercept is found by setting y=0 and solving for x. The y-intercept is found by setting x=0 and solving for y. Try and remember that when you are finding an intercept, you are always setting the other coordinate to zero.
For this parabola, we can find the y-intercept by setting x=0 and solving for y. That is,
Another way of writing the y-intercept is in point form `(0,-4)`.
To find the x-intercept, we need to do a little more work. We set y=0 and solve for x.
`0=x^2-4` this can be rearranged to solve for x.
`x^2=4` now take square roots of both sides
This means there are two x-intercepts. One is at x=2, and the other is at x=-2. These can also be written in point form `(2,0)` and `(-2,0)`.
= (X-2)(X+2) [since (a^2-b^2)=(a-b)(a+b)
So if Y=0 then x=2 or x=-2 ;Here the parabola intecept x-axis
If x=0 then Y=-4;Here the parabola intercept y-axis
y intercept= -4