# How to find the square root of a no. by division method ?

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sorry I can write example and working rule. On source you can find result.Software package not working.

i sqrt(117.1)

I. 117.10

II make pairs from right 1,17,10

III 1 can divide 1 (intger division) quotient 1 remainder 0

IV 1+1 =2

V divide 17 ( first pair by ) 2x , x=0,1,2, ,9

least 20 can not devide 17 ,so place 0 right to quotient 1 i.e ,new quotient 10.

divisior = 20+0=20

Vi Now carry second pair along side 17 ,1710

divide 1710 by 20x , x=0,1,2,...9 such that

20x multiply by x is less than 1710

in this example it is 8

208 x 8= 1664

Thus new quotitent =108

remainder =1710-1664=36

since in number decimal is one pair left ,from right.

so decimal in quotient is after one ,place from right

i.e 10.8

To calculate the square root of a decimal number.The following steps are

1. Separate the number into two groups from the decimal point (the integer part and the decimal part).

2. If the radicand has an odd number of decimal digits, add a zero to the right.

3.Disregard the presence of the decimal point and extract the square root of the resulting number.

4. In the root, from the right, place as many decimal numbers as there are a number of pairs of decimal places under the radicand. In the remainder and also from the right, place as many decimal numbers as there are decimal places under the radicand.

**Sources:**