How to find the inverse Laplace transform of the following functions. 3 / (s^2 +4) answer is 3/2 sin(2t)

Expert Answers

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We know that:

If `y(s)= b/(s^2 + b^2), `

`==gt y(t) = sin(bt)`

We are given that:

`y(s) = 3/(s^2+ 4)`

We will rewrite as:

`y(s)= 2/(s^2 + 2^2) * 3/2 `

`==gt y(s)= (3/2) 2/(s^2 + 2^2)`

==> y(t)= 3/2 * sin(2t)

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