How to find integral -csc^2x/cotx^1/2 dx?

1 Answer

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llltkl | College Teacher | (Level 3) Valedictorian

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The integral `int(-csc^2x)/((cotx)^(1/2)) dx` has to be determined.

Make the substitution: `cotx=u`

Then `-csc^2xdx=du`

The given integral takes the form after substitution:



`=u^(-1/2+1)/(-1/2+1)+C` (where C is the constant of integration)



Put back the value of u to get the final answer as: