# A 49.9 kg wagon is towed up a hill inclined at 16.9 degrees with respect to the horizontal. The tow rope is parallel to the incline and has a tension of 154 N in it. Assume that the wagon starts...

A 49.9 kg wagon is towed up a hill inclined at 16.9 degrees with respect to the horizontal. The tow rope is parallel to the incline and has a tension of 154 N in it. Assume that the wagon starts from rest at the bottom of the hill, and neglect friction. How fast is the wagon going after moving 20.1 m up the hill?

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### 1 Answer

A 49.9 kg wagon is towed up a hill inclined at 16.9 degrees with respect to the horizontal. The tow rope is parallel to the incline and has a tension of 154 N in it. The acceleration due to gravity parallel to the incline is given by 9.8*sin 16.9 = 2.84

Due to the force acting on the wagon, it is accelerated by 154/49.9 = 3.086 m/s^2. Subtracting the acceleration due to the component of gravitational attraction parallel to the incline, the net acceleration up the incline is 0.237 m/s^2

After moving 20.1 m up the hill, the speed of the wagon is sqrt(2*0.237*20.1) = 3.089 m/s

**The speed of the wagon after 20.1 m is 3.089 m/s.**