How far apart must two electrons be if the force between them is to be 2.0 x 10^-12 N.

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The force of attraction between two oppositely charged bodies with charges q1 and q2 is equal to F = C*q1*q2/r^2, where r is the distance between the bodies and C = 8.987*10^9 N*m^2/C^2

The charge on an electron is -1.602*10^-19 C. There is a repulsive force between the two electrons. For it to be equal to 2*10^-12 N let the distance between the two be D. This gives:

2*10^-12 = 8.987*10^9*(1.602*10^-19)^2/D^2

=> D^2 = 8.987*10^9*(1.602*10^-19)^2/(2*10^-12)

=> D^2 = 1.153*10^-16

=> D = 1.0738*10^-8 m

The electrons would have to be 1.0738*10^-8 m apart for the force between them to be 2*10^-12 N

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