# How to express an acceleration of 13 m/s/ms into m/s^2? Then how to show in terms of g?

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Since acceleration = `Delta` velocity/`Delta` time,

the calculation of acceleration usually results in the unit of (m/s)/s or m/s2, read as "meters per second per second" or "meters per second squared".

13 ms (millisecond) = .001 sec. so:

13 m/s/ms = 13 m/s/.001 sec = 13,000 m/s/s =**13,000 m/s2**` <br> `

(13,000 m/s2)/(9.8 m/s2) = 1326.5

so 13 m/s/ms is 1326.4g, or **1300 g **using proper significant digits

g is often rounded to 10 m/s2, which would give the same answer when significant digits are considered.