How to express an acceleration of 13 m/s/ms into m/s^2? Then how to show in terms of g?
Since acceleration = `Delta` velocity/`Delta` time,
the calculation of acceleration usually results in the unit of (m/s)/s or m/s2, read as "meters per second per second" or "meters per second squared".
13 ms (millisecond) = .001 sec. so:
13 m/s/ms = 13 m/s/.001 sec = 13,000 m/s/s =13,000 m/s2` <br> `
(13,000 m/s2)/(9.8 m/s2) = 1326.5
so 13 m/s/ms is 1326.4g, or 1300 g using proper significant digits
g is often rounded to 10 m/s2, which would give the same answer when significant digits are considered.