# How do you write a short paragraph And solve any simple y=mx+b equation ?How to solve any simple y=mx+b equation and how would you write it in a short paragraph

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### 2 Answers

You need to know that `y = mx+b` represents the slope intercept form of equation of a line, such that:

`m` represents the slope of the line

`b ` represents y intercept

You need to solve for x the equation `y = mx + b` , hence, you need to isolate the term that contains `x` to the left side, such that:

`-mx = -y + b`

You need to multiply by `-1` such that:

`mx = y - b`

Dividing by m yields:

`x = (y - b)/m`

**Hence, evaluating the solution to the given equation `y = mx + ``b` , if `m,b!=0` , yields `x = (y - b)/m` .**

If you need to sketch the graph of the function, you need to have at least two points, hence, you may find `x` and `y` intercepts, such that:

`x ` intercept => `y = 0 => mx + b = 0 => mx = -b => x = -b/m`

**The graph intercepts `x` axis at `(-b/m,0).` **

y intercept

`x = 0 => m*0 + b = y => y = b`

**The graph intercepts `y ` axis at `(0,b).` **

**Notice that if the slope `m` is negative, the line descends and if the slope is positive, the line goes up.**

### User Comments

The equation of a straight line is usually written this way:

**y** = how far up

**x** = how far along

**m** = Slope or Gradient (how steep the line is)

**b**= the Y Intercept (where the line crosses the Y axis)**y**= how far up

how you find m = change in y / change in x

## Example 1

m = 2 1 = 2

b = 1

*(where the line crosses the Y-Axis)*