# Write the expression `cos(2*sin^-1(x))` as an algebraic expression in x for x > 0?

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### 1 Answer

The expression `cos(2*sin^-1(x))` has to be expressed as an algebraic expression in x.

`cos(2*sin^-1(x))`

=> `1 - 2*sin^2(sin^-1(x))`

=> `1 - 2*(sin(sin^-1(x))^2`

=> `1 - 2*x^2`

**The expression `cos(2*sin^-1(x))` can be written as **`1 - 2*x^2`

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