How do you solve (cos x sin 2x = 0)?

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justaguide | College Teacher | (Level 2) Distinguished Educator

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We have to solveĀ  cos x sin 2x = 0

First use sin 2x = 2 sin x cos x

cos x sin 2x = 0

=> cos x( 2 sin x cos x) = 0

=> 2 sin x (cos x)^2 = 0

So we have sin x = 0

=> x = 2*n*pi

cos x = 0

=> x = pi/2 + 2*n*pi

So x can be 2*n*pi and pi/2 + 2*n*pi

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