how do you solve 5x-6/4+3>12  

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rcmath | High School Teacher | (Level 1) Associate Educator

Posted on

***Being clear is really important when writing this type of question. I'm unsure if the problem is (5x-6)/(4+3)>12, 5x-(6/4)+3>12, or (5x-6)/4 + 3>12.

***The above solution is correct if your problem was the first case situation. However, here's an important correction: solution is x>18 which is written as `(18,oo)` . Your answer is all numbers larger than 18, but not 18.

***If the problem is the last case I suggested then 
`(5x-6)/4>9=>5x-6>36=>5x>42=>x>42/5`

Hence solution set `(42/5,oo)`

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edobro | Student, Grade 11 | (Level 2) Honors

Posted on

It's really easy.

First you know that 4+3=7 so you can write it down as: 5x-6/7>12

Multiply both sides by 7 and you have

5x-6>84

5x>84+6

5x>90 Divide both sides by 5 and you have your answer 

x>18

So for every value of x>18 we will get a result that works so this interval of x goes from (-∞,17], or the solution is for every x element 

(-∞,17].

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