# how do you solve 5x-6/4+3>12

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***Being clear is really important when writing this type of question. I'm unsure if the problem is (5x-6)/(4+3)>12, 5x-(6/4)+3>12, or (5x-6)/4 + 3>12.

***The **above solution** is correct if your problem was the *first* case situation. However, here's an **important correction**: solution is x>18 which is written as `(18,oo)` . Your answer is all numbers larger than 18, but not 18.

***If the problem is the *last* case I suggested then

`(5x-6)/4>9=>5x-6>36=>5x>42=>x>42/5`

Hence solution set `(42/5,oo)`

It's really easy.

First you know that 4+3=7 so you can write it down as: 5x-6/7>12

Multiply both sides by 7 and you have

5x-6>84

5x>84+6

5x>90 Divide both sides by 5 and you have your answer

x>18

So for every value of x>18 we will get a result that works so this interval of x goes from (-∞,17], or the solution is for every x element

(-∞,17].