How do you simplify this: 2x/3 * x^3/6x-9 / x^2/9? The little arrow (^) means the square root.
`((2x)/3)* (x^3/(6x - 9))-: (x^2/9)`
factor 6x - 9 to 3(2x - 3); multiply by the reciprocal of `x^2/9`
` ` `((2x)/3)* (x^3/(3(2x-3)))*(9/x^2)`
` `cancel the 2 three's with the 9; cancel x^2 with x^3 leaving an x:
you'll now have:
multiply through gives you:
`(2x^2)/(2x - 3)`