how do you find where a equation intersects the x axis for y=(x-5)^2?
Given the equation:
`` We need to find where the curve y intersects with the x-axis.
When the curve meets the x-axis, then the value of y is 0.
Then, we will substitute with y= 0 and then determine the value of x-coordinate.
==> `y= (x-5)^2 = 0`
`==> x-5= 0`
`==> x = 5`
``Then, the curve y intersects with the x-axis at the point (5, 0).
algebraeically solve it, by square rooting both sides to now get x-5=0 then sove for x, now x=5 this is your x intercept
To find an x-intercept you make y=0
(x-5)^2 = 0
take the power over and square root the 0
(x-5) = 0
take the five to the other side and change the sign
x = 0+5
x = 5