# How do you find the equation of each trace for: -20x+10y+50z = 100? (I've already found x-intercept= -5, y-int =10, & z-int=2.)

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Student Comments

aruv | Student

Given equation of plane is

-20x+10y+50z=100

-2x+y+5z=10 (i)

To find the equation of each trace, substitute z=0, y=0, and x=0 in (i). Thus we will get three equations i.e.

-2x+y=10

-2x+5z=10

y+5z=10

These are equation of line in respectively xy-plane, xz-plane, and yz-plane.