# How do you do point-slop, slope intercept, and standard form for the coordinates (-2,6) (-4,10)?

Expert Answers
justaguide | Certified Educator

The equation of the line joining the points (-2, 6) and (-4, 10) has to be expressed in different forms.

The equation of the line in point slope form is: `(y - 10)/(x +4) = (6 - 10)/(-2 +4)`

Simplifying this gives

=> `(y - 10)/(x +4) = (-4/2)`

=> `(y - 10)/(x +4) = -2`

=> y - 10 = -2x - 8

The slope-intercept form is y = -2x + 2

The standard form of the line is 2x + y - 2 = 0

Wiggin42 | Student

(-2,6) (-4,10)

First find slope which is the change in y over the change in x:

10 - 6 / (-4 + 2) = 4/-2 = -2

Put this into point-slope form:

y - 6 = -2(x + 2)

To get into slope-intercept distribute and solve for y:

y = -2x - 4 + 6

y = -2x + 2

To get into standard, rearrange so that x and y are on the same side:

2x + y = 2

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