how do i write a double replacement reaction (balanced) between sulfuric acid and magnesium hydroxide

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A double replacement reaction takes place between two ionic compounds, and follows this pattern:

`(A^+ B^-) + (C^+ D^-) -> (A^+ D^-) + (C^+ B^-)`

The ionic compounds are just trading "partners", so to speak.

The Compounds:

Sulfuric acid has the formula `H_2 SO_4`

It is composed of two Hydrogen...

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A double replacement reaction takes place between two ionic compounds, and follows this pattern:

`(A^+ B^-) + (C^+ D^-) -> (A^+ D^-) + (C^+ B^-)`

The ionic compounds are just trading "partners", so to speak.

The Compounds:

Sulfuric acid has the formula `H_2 SO_4`

It is composed of two Hydrogen ions, with a total charge of +2, and one sulfate ion, with a charge of -2.

Magnesium hydroxide has the formula `Mg(OH)_2`

It is composed of one Magnesium ion, with a total charge of +2, and two hydroxide ions, each with a charge of -1.

The Reaction:


`(H_2^+2)(SO_4^-2) + (Mg^+2)(OH)_2^-2`

Double replacement:

`(H_2^+2)(OH)_2^-2) + (Mg^+2)(SO_4^-2)`

which gives us

`H_2(OH)_2 + MgSO_4`

The hydrogen-hydroxide compound has a formula of

`H_4O_2`

which simplifies to

`2 H_2O`

So, the complete reaction is:

`H_2SO_4 + Mg(OH)_2 -> MgSO_4 + 2H_2O`

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