How do I solve this problem? `-2/3x=5`
So here, we need to figure out what value for `x` will allow the following equation to be true:
`-2/3x = 5`
We need to answer the question "Negative two-thirds of what number is 5?"
Well, we can manipulate this a number of ways. We can start by multiplying both sides by 3 to get rid of the fraction. Remember, if you have a fraction with the same factor in the numerator and denominator, you can cancel them out!
`-(3*2)/3 x= 3*5`
Now, we're going to do the same thing, but with division. We're going to divide both sides by -2 so we can cancel out the -2 with x:
`-2/-2x = 15/-2`
`x = -15/2`
We can't simplify the fraction much further. We can get a decimal though!
`x = -7.5`
So, there's our answer. A quicker option, if you understand what we just did, is to multiply by the multiplicative inverse of the fraction. In our case, that would mean multiplying by `-3/2`:
`-3/2*-2/3 x = -3/2*5`
This pretty much combines the two steps we took into one step. We get the same answer, but it's just quicker if you undestand how it works!
I hope that helps!
Since you are trying to isolate x do the inverse
-2/3x = 5
To get " x " alone I will have to divide -2/3 on both sides
5 X -3/2 = -15/2
By dividing on both sides , your equation should look like :
x = -15/2 which is your answer ; you can also change it into a mixed number which is -7 1/2
``multiply both sides by 3 then divide by -2
We need to isolate x. To do this, we have to undo whatever is being done to x. Right now, x is being multiplied by -2/3 . To undo this, we have to divide by -2/3. Which is the same as multiplying by the reciprocal -3/2.
x = 5(-3/2)
x = -15/2
`-2/3x` = 5
Solve for the variable
do the inverse fraction
`(3/2)` (-`2/3x)` = 5 `(3/2)`
fist you multiply the 2 sides by the denominator to get rid of the fraction
`3xx -2/3 x = 5xx3 `
this will cancel the 3
now divide by -2 to get x by itself
or -7 1/2