how do i solve this equation?   x^2 + 3x + 2

Expert Answers
sciencesolve eNotes educator| Certified Educator

You may use the quadratic formula such that:

`x_(1,2) = (-3+-sqrt(3^2 - 4*1*2))/2`

`x_(1,2) = (-3+-sqrt(9-8))/2`

`x_(1,2) = (-3+-1)/2`

`x_1 = (-3+1)/2 =gt x_1 = -1`

`x_2 = (-3-1)/2 =gt x_2 = -2`

Hence, evaluating solutions to equation `x^2 + 3x + 2 = 0 ` yields  `x_1 = -1`  and `x_2 = -2` .

sarahyama | Student

yamero,

I suppose that you missed to put that equation is equal to zero.

To solve the question above, you should first factor the equation to (X+2)(X+1)=0

then X can be either -2 or -1 so that the value in the parenthesis becomes zero.

malkaam | Student

x^2 + 3x + 2

You can solve by considering it as a quadratic equation x^2 + 3x + 2=0

i.e. ax^2+bx+c=0

Where a=1

           b=3

           c=2

Quadratic Formula,

    = [-3+sqrt{3^2-4(1)(2)}]/2(1)           =[-3-sqrt{3^2-4(1)(2)}]/2(1)

    = [-3+sqrt{9-8}]/2                            =[-3-sqrt{9-8}]/2

    = [-3+sqrt{1}]/2                               =[-3-sqrt{1}]/2

    = [-3+1]/2                                        =[-3-1]/2

    = -2/2                                               =-4/2

  x= -1                                                 x=-2

taangerine | Student

x^2 + 3x + 2=0

Factor, then solve.

(x+2)(x+1)

x+2=0

x=-2

x+1=0

x=-1

givingiswinning | Student

x^2 + 3x + 2

(x+2) (x+1)
 
x+2 = 0
x= -2
 
x+1 = 0
x = -1
fashionableb1 | Student

x^2 + 3x + 2

 
(x+2) (x+1)
 
 
x+2 = 0  x+1 = 0
 x= -2 x = -1
atyourservice | Student

x^2 + 3x + 2

this factors to:
 
(x+2) (x+1)
 
because 2 x 1 = 2(c) and 2+1 = 3 (b)
 
now set them equal to 0
 
x+2 = 0
x= -2
 
x+1 = 0
x = -1
princessenotes | Student

(x+2) (x+1)

x = -2 or -1

 

If you need anymore help, please contact my teacher at helpmathtutor@gmail.com

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