# How do I solve functions with fractions like: y=2/3x+1 or y=3/4x-2.

I think by y = 2/3x + 1, you mean y = (2/3)*x + 1.

So to find the value of y in this case, multiply x with (2/3) and add 1.

Similarly for y = (3/4)x - 2, multiply x with (3/4) and subtract 2 from the result.

In...

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I think by y = 2/3x + 1, you mean y = (2/3)*x + 1.

So to find the value of y in this case, multiply x with (2/3) and add 1.

Similarly for y = (3/4)x - 2, multiply x with (3/4) and subtract 2 from the result.

In case you mean y = 2/(3x) +1, you will:

1. first have to multiply x with 4
2. then divide 2 by the result you get

For y = 3/(4x) + 1,

1. first multiply x with 4
2. divide 3 by the result

In case you mean y =2/(3x+1),

1. first multiply x and 3
2. add one to the result
3. finally divide 2 by what you get after step 2.

Similarly for y =3/(4x - 2),

1. first multiply x with 4
2. then subtract 2 from it
3. and finally divide 3 by the result after step 2.

[It is essential to use brackets when you write these kinds of functions so that the order of operations is clear.]

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