Jimmy shot the basketball from a height of four feet with an upward velocity of 12 ft/sec. The acceleration due to gravity is 32 ft/sec^2.

Take the independent variable as the time elapsed after the ball is thrown and the dependent variable as the height of the ball.

**y = f(t) = 4 + 12*t - (1/2)*32*t^2 = 4 + 12*t - 16t^2**

The height of the basketball plotted against time is a parabola. The highest point of the parabola is the value of y at t which is the solution of f'(t) = 0.

f'(t) = 12 - 32t

12 - 32t = 0

=> t = 12/32

At t = 32/12, y = 4 + 12*(12/32) - 16*(12/32)^2

=> 4 + 4.5 - 2.25

=> 6.25

**The maximum height of the ball is 6.25 ft. It does not make it to the ten-foot tall hoop.**

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