How do I solve the following equation :  4(2y+1)=2(12-y) I know the answer is y=2 but i do not know how to work it out

Expert Answers

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You have to solve the equation 4(2y+1) = 2(12-y).

First let's start with 4(2y+1) = 2(12-y)

open the brackets

=> 4*2y + 4*1 = 2*12 - 2*y

=> 8y + 4 = 24 - 2y

now move the terms with y to one side, and the numeric terms to the other side. Remember that when you move a term to the other side of the equation, its sign changes

=> 8y + 2y = 24 - 4

=> 10y = 20

divide both the sides by 10

=> y = 20/10 = 2.

That's how you get y = 2. Hope it's clear now.

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