`3|x| + 2 lt 17`

To solve, isolate the absolute value. To do so, subtract both sides by 2.

`3|x|+2-2lt17-2`

`3|x|lt15`

And divide both sides by 3.

`(3|x|)/3lt15/3`

`|x|lt5`

Next, drop the absolute value sign. Note that when dropping the absolute value sign in equality equation for less than ( `|x|lta ` ), the resulting equation is `-altxlta` .

`-5ltxlt5`

**Hence, the solution to the inequality equation `3|x|+2lt17` is `-5ltxlt5` . In interval notation, the solution is `(-5, 5)` .**

To solve, isolate the absolute value. To do so, subtract both sides by 2.

And divide both sides by 3.

Next, drop the absolute value sign. Note that when dropping the absolute value sign in equality equation for less than ( ), the resulting equation is .

Hence, the solution to the inequality equation is . In interval notation, the solution is .

thank you !!