# How do I simplify this: 4+ √24 / 2 4-√24 /2 Four plus or minus the square root of twenty-four divided by 2

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24 = 4*6

`sqrt24 `

`= sqrt(4*6)`

`= sqrt4*sqrt6`

`= 2sqrt6`

Our question is simplifying `4+-sqrt24/2`

`4+-sqrt24/2`

`= 4+-(2sqrt6)/2`

`= 4+-sqrt6`

**So the answer is **`4+-sqrt6`

** If your question is**` (4+-sqrt24)/2`

`(4+-sqrt24)/2`

`= (4+-2sqrt6)/2`

`= 4/2+-2sqrt6/2`

`= 2+-sqrt6`

* So answer is* `2+-sqrt6`

To reduce `sqrt24` , we need to factor 24 which is `24=2 times 2 times 2 times 3`. Since the square root of a square is the number, we can simplify a bit.

`sqrt24`

`=sqrt{2 times 2 times 2 times 3}`

`=sqrt{4 times 6}`

`=sqrt4 sqrt 6`

`=2sqrt6`

**This means that `(4-sqrt24)/2` becomes `(4-2sqrt6)/2` which is `2-sqrt6` .**

Well I got the answer...

(4+√24) / 2 = 2+√6

Still not really clear on how to reduce the square root of 24 properly, if anyone cares to help explain it would be much appreciated xD