Prove `lim_(x->0) sqrt(4) - x` = 2

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You have to find the value of `lim_(x->0)` [` ``sqrt(4) - x`]

As the value of x changes, so does the value of `sqrt(4) - x`. The problem requires the value of ` ``sqrt(4) - x` as x approaches 0.

Now you can see that whether x approaches 0 from...

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You have to find the value of `lim_(x->0)` [` ``sqrt(4) - x`]

As the value of x changes, so does the value of `sqrt(4) - x`. The problem requires the value of ` ``sqrt(4) - x` as x approaches 0.

Now you can see that whether x approaches 0 from the right hand side of the origin or from the left hand side of the origin, the value of `sqrt(4) - x` is the same.

The value can be found by substituting x with 0; this gives `sqrt(4) - 0` = `sqrt(4)` = 2.

The value of `lim_(x->0) sqrt(4) - x` = 2.

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