# How do I plot the position vector given by r(t)=ti+t^2j+tk, such that t>(or equal to) 0?

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### 1 Answer

You need to plug some positive values for t in the equation of vector function such that:

`t = 0 =gt x=0;y=0,z=0`

`` `t=1 =gt x=1 ; y= 1^2 = 1 ; z = 1`

`t = 2 =gt x = 2 ; y = 4 ; z = 2`

`t = 3 =gt x = 3 ; y = 9 ; z = 3`

`` `t = n =gt x =n ; y =n^2 ; z = n`

**Hence, since t varies, the graph is a curve in space and giving values to t yields position vectors `barr(n) = nbar i +n^2 bar j + n bar k` , at the instants t=0,1,2,3,...,n.**