# how do i find the center, transverse axis, vertices, foci and asymptotes for the hyperbola? 2x^2-y^2=4 help

Rico Grant | Certified Educator

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Given the hyperbola `2x^2-y^2=4` :

The general form is `(x-h)^2/a^2-(y-k)^2/b^2=1` for a hyperbola with a horizontal major axis. The center will be at (h,k).

For hyperbolas centered at the origin, the asymptotes are given by `y=+-b/ax` . The transverse axis will have length 2a....

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