How do I figure out this problem: 3(x+9)?
You need to use the distributivity of multiplication over addition, hence, you need to perform the following steps, such that:
`3(x + 9) = 3*x + 3*9` (multiply each term inside round brackets by 3)
`3(x + 9) = 3x + 27` (perform the multiplication of constants 3 and 9)
Hence, using the property of distributivity, yields `3(x + 9) = 3x` + `27` .
You need to distribute the 3 over the parenthesis. This means that you must multiply each term inside the parenthesis by the outside term which in this case is 3.
Luckily, there are only two inside terms so we get:
3x + 27
When doing these problems, watch out for negative signs since you'll have to distribute that negative as well.
3(x+9) distribute the three to the number in the parenthesis, meaning you multiply the numbers inside by 3
you will end up with
3x+27 and that's it
You need to distribute the 3 through the term in parenthesis. The integer 3 is multiplying the whole term (x+9). To solve, multiply 3 by the first term x, which will give you 3x, then by the second term 9, which will give you 27. Therefore, 3(x+9) = 3x + 27.