How do I figure the area of a circle that is d = 6x + 2?
The formula for the area of a circle is a=pi (r^2), where r equals the radius. You have been given the diameter; you have to cut that in half to get the radius. If you factor out "2" from your given diameter, d=2(3x+1). divide that by 2:
That must be squared because it is the radius, and you need radius squared before you can determine area. You then have:
(3x+1)(3x+1), which equals 9x^2+6x+1.
Multiply all of that by pi to get the area--you will have to multiply pi by each of the terms, and your area will be in terms of x; using 3.14 for pi, you have:
Since the diameter, d is given, the area, A of the circle can be calculated :A =Pi times the square of the half the diametr.Half the diameter is also the radius of the cicle.
A=Pi*(d/2)^2. d is given 6x+2 . Substitute it in the formula.
=Pi*[9x^2+12x+4]. Value of Pi=3.141593
NB:It is better to use A=Pi(3x+2)^2 for calculation purpose rather than the expanded form.
Given d = 6x + 2 we need to find area.
The area of a circle is
( pi ) ( r ) ^2
And r, radius, is half the diameter so it can be written as d/2
Plug this into our formula and we get:
A = ((pi ) (d)^2 )/4
Now we can directly plug in out given diameter:
A = ( (pi) (6x + 2)^2 ) /4