How do I factor the equation x^2 + 4x-5?
You may use the following alternative method to convert the standard form of quadratic equation into its factored form, such that:
`ax^2 + bx + c = a(x - x_1)(x - x_2)`
`x_1,x_2 ` represent the solutions to the given equation
Hence, you need to evaluate the solutions to quadratic equation `x^2+ 4x - 5 = 0` using quadratic formula, such that:
`x_(1,2) = (-4+-sqrt(16+20))/2 => x_(1,2) = (-4+-sqrt36)/2`
`x_(1,2) = (-4+-6)/2 => x_1 = 1 ; x_2 = -5`
Replacing `a = 1 ` and `x_1 = 1 ; x_2 = -5 ` in factored form of the given quadratic equation, yields:
`x^2+ 4x - 5 = (x - 1)(x + 5)`
Hence, evaluating the factored form of the given quadratic equation, yields `(x - 1)(x + 5).`
The expression x^2 + 4x - 5 has to be factored.
x^2 + 4x - 5
= x^2 + 5x - x - 5
= x(x + 5) - 1(x + 5)
= (x - 1)(x + 5)
The factored form of x^2 + 4x - 5 = (x - 1)(x + 5)