# How do i do this problem: 5 less than the product of 5 and a number y is 22

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Convert the written question to an algebraic equation:

The product of 5 and a number y is written 5y.

5 less than the product is written 5y-5.

Typically is indicates equality.

So we have 5y-5=22.

Add 5 to both sides to get 5y=27. Now divide both sides to get:

`y=27/5 ` .

Check: 5 times the number y is `5 * 27/5 ` or 27. % less than 27 is 22 as required.

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The solution is `y=27/5 `

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How do i do this problem: 5 less than the product of 5 and a number y is 22

5 **less than** the **product** of 5 and a number y **is** 22

A number y has to be determined such that 5 less than the product of 5 and the number y is 22.

The product of the number and 5 is 5y. 5 less than this is 5y - 5

This is equal to 22. We get an equation:

5y - 5 = 22

Add 5 to both the sides of the equation

5y - 5 + 5 = 22 + 5

5y = 27

Divide both the sides of the equation by 5

(5y)/5 = 27/5

y = 27/5

This gives the required value of y as 27/5

5 less than the product of 5 and a number y is 22.

The second part "product of 5 and a number y" means 5y, the first part "5 less than the product of 5 and a number y" means 5y - 5 since we've already established what the second part means it's obvious that we have to subtract 5 from 5y, and the last part means that 5y - 5 = 22.

5y - 5 = 22

Now to find the value of y the unknown variable y is to be isolated to one side.

5y - 5 + 5 = 22 + 5 Add 5 to both sides

5y = 27

5y/5 = 27/5 Divide both sides by 5

y = 27/5 Answer.