# How do I change y-2x=7 into slope intercept form, and into standard form??

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Write the equation, `y - 2x = 7` into slope-intercept form and standard form.

To change to slope intercept form: `y = mx+b.`

Add 2x to both sides to isolate y.

`y-2x+2x = 7 + 2x`

` ``y = 2x+7`

`y-2x = 7` **in slope-intercept form is** `y = 2x+7` .

**Standard Form:** the standard form of a line is in the form Ax + By = C where A is a positive integer, and B, and C are integers.

`y-2x =7` Multiply every term by -1 to have x-coefficient positive.

`-1(y -2x)=7 rArr -y + 2x = -7`

Rearrange in `ax+by = c` form

`2x - y = -7`

` ``y-2x=7`** in standard form is** `2x-y=-7` .

Slope-intercept form of a linear equation looks as y = mx + b, where m is the slope and b is the y-intercept.

To change the equation y- 2x = 7 into slope-intercept form, isolate y by adding 2x to both sides:

**y = 2x +7**

Here, m = 2 is the slope and b = 7 is the y-intercept.

In standard form, a linear equation looks as ax + by = c, where a, b, and c are integers.

The given equation is already almost in standard form. All is needed is to exchange the order of the variables:

-2x + y = 7

One can also multiply both sides of the equation by - 1:

**2x - y = -7**

**Answer: **

**y = 2x + 7 (slope-intercept form)**

**2x - y = -7 (standard form)**

y-2x=7

simply add 2x to both sides to get slope intercept form

y= 2x+7

is slope intercept form which is the same as y=mx+b to get this

whereas

standard form : 2x-y-7

y-2x=7 slope intercept form= y = mx + b standard form= ax + by = c

to get the slope intercept form just add 2x to both sides you will end up with

y=2x+7

to get the standard form just minus 7 on both sides

y-7=2x and minus y

-7=2x-y just flip it

2x-y=-7 and voila!

That helped clear my confusion! Thank you very much!