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Write the equation, `y - 2x = 7` into slope-intercept form and standard form.
To change to slope intercept form: `y = mx+b.`
Add 2x to both sides to isolate y.
`y-2x+2x = 7 + 2x`
` ``y = 2x+7`
`y-2x = 7` in slope-intercept form is `y = 2x+7` .
Standard Form: the standard form of a line is in the form Ax + By = C where A is a positive integer, and B, and C are integers.
`y-2x =7` Multiply every term by -1 to have x-coefficient positive.
`-1(y -2x)=7 rArr -y + 2x = -7`
Rearrange in `ax+by = c` form
`2x - y = -7`
` ``y-2x=7` in standard form is `2x-y=-7` .
Slope-intercept form of a linear equation looks as y = mx + b, where m is the slope and b is the y-intercept.
To change the equation y- 2x = 7 into slope-intercept form, isolate y by adding 2x to both sides:
y = 2x +7
Here, m = 2 is the slope and b = 7 is the y-intercept.
In standard form, a linear equation looks as ax + by = c, where a, b, and c are integers.
The given equation is already almost in standard form. All is needed is to exchange the order of the variables:
-2x + y = 7
One can also multiply both sides of the equation by - 1:
2x - y = -7
y = 2x + 7 (slope-intercept form)
2x - y = -7 (standard form)
simply add 2x to both sides to get slope intercept form
is slope intercept form which is the same as y=mx+b to get this
standard form : 2x-y-7
y-2x=7 slope intercept form= y = mx + b standard form= ax + by = c
to get the slope intercept form just add 2x to both sides you will end up with
to get the standard form just minus 7 on both sides
y-7=2x and minus y
-7=2x-y just flip it
2x-y=-7 and voila!
That helped clear my confusion! Thank you very much!
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