You need to apply the principle of conservation of mechanical energy such that: `mgh = (mv^2)/2 =gt 2gh = v^2 =gt v = +-sqrt(2gh).`

Considering the motion of object frictionless, hence `v = sqrt(2gh).`

The problems provides the value of height, hence the angle made by slope to x axis...

## Unlock

This Answer NowStart your **48-hour free trial** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

You need to apply the principle of conservation of mechanical energy such that: `mgh = (mv^2)/2 =gt 2gh = v^2 =gt v = +-sqrt(2gh).`

Considering the motion of object frictionless, hence `v = sqrt(2gh).`

The problems provides the value of height, hence the angle made by slope to x axis is of no need in this problem. You need to know the angle only if the length of slope is known but the height is not given.

Substituting is`9.8 m/(s^2)` for g and 36 m for h yields:v = `sqrt(2*9.8*36) ` => `v~~ 26.56 m/s`

**Hence, evaluating the velocity of object sliding down from the top of slop yields: v~~ 26.56 m/s.**