We have to find the integral of e^ sqrt x / sqrt x.
Let u = sqrt x
=> du/dx = 1/2* sqrt x
=> 2* du = dx / sqrt x
Int [ (e^ sqrt x / sqrt x) dx]
=> Int [ e^u * (dx/sqrt x)]
=> Int...
See This Answer Now
Start your subscription to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.
Already a member? Log in here.
We have to find the integral of e^ sqrt x / sqrt x.
Let u = sqrt x
=> du/dx = 1/2* sqrt x
=> 2* du = dx / sqrt x
Int [ (e^ sqrt x / sqrt x) dx]
=> Int [ e^u * (dx/sqrt x)]
=> Int [ e^u * 2 du]
=> 2*e^u + C
replace u = sqrt x
=> 2e^ sqrt x + C
Therefore the required integral is 2*e^ sqrt x + C