We have to find the integral of e^ sqrt x / sqrt x.

Let u = sqrt x

=> du/dx = 1/2* sqrt x

=> 2* du = dx / sqrt x

Int [ (e^ sqrt x / sqrt x) dx]

=> Int [ e^u * (dx/sqrt x)]

=> Int [ e^u * 2 du]

=> 2*e^u + C

replace u = sqrt x

=> 2e^ sqrt x + C

**Therefore the required integral is 2*e^ sqrt x + C**

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now