We have to find the integral of e^ sqrt x / sqrt x.

Let u = sqrt x

=> du/dx = 1/2* sqrt x

=> 2* du = dx / sqrt x

Int [ (e^ sqrt x / sqrt x) dx]

=> Int [ e^u * (dx/sqrt x)]

=> Int...

## See

This Answer NowStart your **subscription** to unlock this answer and thousands more. Enjoy eNotes ad-free and cancel anytime.

Already a member? Log in here.

We have to find the integral of e^ sqrt x / sqrt x.

Let u = sqrt x

=> du/dx = 1/2* sqrt x

=> 2* du = dx / sqrt x

Int [ (e^ sqrt x / sqrt x) dx]

=> Int [ e^u * (dx/sqrt x)]

=> Int [ e^u * 2 du]

=> 2*e^u + C

replace u = sqrt x

=> 2e^ sqrt x + C

**Therefore the required integral is 2*e^ sqrt x + C**