How to determine the coordinates of the vertex of parabola, v(h,k), if y=x^2-6x+8.

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The equation of the parabola is y = x^2 - 6x + 8

y = x^2 - 6x + 8

=> x^2 - 6x + 9 - 1

=> (x - 3)^2 -1

This is the standard form of a parabola y = (x - h)^2  + k

The vertex is at ( 3, -1)

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