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Your question is not very clear.
If the magnitude of a force is given and that the force is acting at an angle to the traditional axes (x & y, i.e. horizontal and vertical), we resolve the force into two components, each acting along the traditional axes. This is done using trigonometry.
If the angle with respect to x-axis (or horizontal) is given, the horizontal component is the cosine of force (i.e., Fcos`Theta` ) and the vertical component is sine of the force (i.e., Fsin`theta` ).
If you are given two forces and the angle between them, then the resultant force can be calculated using parallelogram law. Suppose the two forces are A and B and the angle between them is `theta` , then the resultant force (F) is given as
`F = sqrt(A^2 + B^2 + 2AB cos theta)`
and the direction of the resultant force is given by
`alpha = tan^(-1) [(Bsin theta)/(A+Bcos theta)]`
hope this helps
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