To solve
2x - y = 5 ...(1)
3x - 2y = 9 ...(2)
using substitution take (1)
2x - y = 5
=> y = 2x - 5
substitute in (2)
3x - 2(2x - 5) = 9
=> 3x - 4x + 10 = 9
=> -x = -1
=> x = 1
y = 2x - 5 = 2 - 5 = -3
The solution of the equations is x = 1 and y = -3
algebra1