# How can I solve the solar cooker parabolic mirror question in the image, please?

*print*Print*list*Cite

Power available in sunlight = 1 KJ/s (per unit area, m^2)

Area of the solar cooker = 1 m^2

Specific Heat Capacity of water = 4190 J/Kg/C

Heat required to boil 1 lt of water from 20 degrees Celsius = mass of water x specific heat capacity x temperature change

= 1 kg x 4190 J/Kg/C x (100-20) Celsius = 3,35,200 J = 335.2 KJ

Assuming 100% capacity of heat transfer from the reflector to the food

Rate of heat generation by the solar cooker = 1 KJ/s/m^2 x 1 m^2 = 1000 J/s

Total time required to boil the water = heat required/heat generation rate

= 335.2 KJ/1 KJ/s = **335.2 sec or 5 minutes and 35 seconds** (about) or **Option C**.

In reality, there would be a number of power losses and the actual heat transfer efficiency would be less than 100% and it will take more time than that calculated above.

Hope this helps.