The integral `int cos(3x+4) dx` has to be determined.
It is known that the integral of cos x is sin x. In cos (3x+4) the cosine of a function of x is being considered.
Use substitution here; let y = 3x + 4
`dy = 3 dx`
`int cos(3x+4) dx`
= `int cos y * (1/3)* dy`
= `(1/3)*int cos y dy`
= `(1/3)*sin y`
replace y by 3x + 4
= `(1/3)*sin(3x+4)`
The integral `int cos(3x+4) dx` is `(sin(3x+4))/3 + C`
See eNotes Ad-Free
Start your 48-hour free trial to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.
Already a member? Log in here.