The solution can be considered as a neutral solution. In order to determine its pH we should get the concentration of OH- in the solution.
We first let a 1 liter of solution of 10^-9 M NaOH.
In a liter of solution there are 10^-9 moles NaOH thus there are...
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The solution can be considered as a neutral solution. In order to determine its pH we should get the concentration of OH- in the solution.
We first let a 1 liter of solution of 10^-9 M NaOH.
In a liter of solution there are 10^-9 moles NaOH thus there are 10^-9 moles OH- (Since moles NaOH = moles Na+ = moles OH-).
Next, remember that neutral water has 10^-7 moles OH or H+ right? So we add the moles of NaOH with the moles of OH derived from water.
10^-9 + 10^-7 = 1.01x10^-7 moles NaOH
pOH = -log (OH-)
pOH = -log (1.01x10^-7)
pOH = 6.99
pH = 14 - pOH
pH = 14 – 6.996
pH = 7.004 ~ 7.00 therefore neutral.