# How to calculate the kpa of the given plate on earth's pressure where: length is 3500mm, height is 2300mm, thickness is 75 mm.

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You seem to want to calculate the pressure exerted by the plate on the earth's surface (specific and the dimensions should have been stated clearly in the drawing).

Pressure exerted = Force/Area

In this case Force is equal to the weight of the plate.

Weight of plate = mass*g ( acceleration due to gravity)

= density*volume*g

Dimensions of plate are length = 3500 mm = 3.5m

Width = 2300 mm = 2.3 m

Thickness = 75 mm = 0.075 m

Assuming the material of construction of plate to be steel ( it has not been stated in the question) , density of steel(assumed) = 7750 Kg/m^3

Volume of plate = 3.5*2.3*0.075 m^3 = 0.60375 m^3

Therefore Weight of one plate = 7750*0.60375*9.8 =45854.8125

Force exerted by plate on the earth = Weight/Area

= 45854.8125/(3.5*2.3)

45854.8125/8.05

= 5696.25 Pascal

= **5.7 KPa**

Assumptions : Material of construction of plate as steel with density(7750 Kg/m^3) , single plate lying flat on the earth surface.