How to calculate the kpa of the given plate on earth's pressure where: length is 3500mm, height is 2300mm, thickness is 75 mm.

This image has been Flagged as inappropriate Click to unflag
Image (1 of 1)
gsarora17 | Student

You seem to want to calculate the pressure exerted by the plate on the earth's surface (specific and the dimensions should have been stated clearly in the drawing).

Pressure exerted = Force/Area

In this case Force is equal to the weight of the plate.

Weight of plate = mass*g ( acceleration due to gravity)

                       = density*volume*g

Dimensions of plate are length = 3500 mm = 3.5m

                                  Width = 2300 mm = 2.3 m

                                Thickness = 75 mm = 0.075 m

Assuming the material of construction of plate to be steel ( it has not been stated in the question) , density of steel(assumed) = 7750 Kg/m^3

Volume of plate = 3.5*2.3*0.075 m^3 = 0.60375 m^3

Therefore Weight of one plate = 7750*0.60375*9.8 =45854.8125

Force exerted by plate on the earth = Weight/Area

                                                   = 45854.8125/(3.5*2.3)


                                                   = 5696.25 Pascal

                                                    = 5.7 KPa

Assumptions : Material of construction of plate as steel with density(7750 Kg/m^3) , single plate lying flat on the earth surface.

Access hundreds of thousands of answers with a free trial.

Start Free Trial
Ask a Question