How to calculate the heat of formation of benzoic acid?Benzoic acid can be burned to produce liquid water and carbon dioxide. The molar enthalpy of combustion for benzoic acid is -3226.6...

How to calculate the heat of formation of benzoic acid?

Benzoic acid can be burned to produce liquid water and carbon dioxide. The molar enthalpy of combustion for benzoic acid is -3226.6 kJ/mol. 
2C6H5COOH (l) -> 6H2O (l) + 14CO2 (g) ΔH= -3226.6 kJ/mol

Given the heats of formation for liquid water is -285.5kJ/mol and carbon dioxide -393.5kJ/mol, calculate the heat of formation of benzoic acid.
I need full calculations for this question, please.

jishnudeepkar | Student

-1613.3= -3611 - ΔH(C6H5.....)

ΔH(C6H5.....)= -3611+ 1613.3        .................

jishnudeepkar | Student

first div reaction by 2

C6H5COOH (l) -> 3H2O (l) + 7CO2 (g) ΔH= -1613.3 kJ/mol

ΔH(rxn)=3ΔH(h20)+ 7ΔH(co2) - ΔH(C6H5.....)

put values and solve ull get value of ΔH(C6H5.....)

Access hundreds of thousands of answers with a free trial.

Start Free Trial
Ask a Question