How are impulse and momentum applied in an egg drop challenge? The challenge was to construct something protective out of 3 sheets of newspaper, tape, and 4 straws so the egg wouldn't break after a fall.

Impulse and momentum are applied in an egg drop challenge in that the protective device will need to reduce the overall impulse the egg has to deal with and then reduce the force of impact.

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Impulse is the change in momentum of an object. There are two impulses that your egg design will have to deal with. The first impulse is from the drop itself. Its momentum will increase due to the net force applied to it. The next impulse is from the landing. If the egg vehicle doesn't bounce, then the two impulses in magnitude are equal!

Imagine that dropping from a meter, the egg has the whole meter to speed up to its speed right before impact (so the egg doesn't break just from falling because the force is small). At impact, that speed will decrease to zero (as long as it doesn't bounce). But, how much distance does it have when it hits compared to the meter? Not much, which means less time to deal with the same magnitude of impulse.

The basic formula for impulse is F*∆t. Since the impulse is constant, F and ∆t are inversely related to each other. More time means less force...

(The entire section contains 505 words.)

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