To solve this problem, split the shape in half by drawing line BD.
Now we have triangle ABD and we know that AB=AD (given)
Therefore `/_B_(1)=/_D_(1)` (isosceles triangle)and we are given that angle A=90.
Therefore, as the angles of a triangle =180 deg and A = 90 deg
Therefore `/_B_(1) =/_ D_(1)=45 deg`
We also know that triangle BCD is isosceles as BC=CD
`therefore` `/_B_(2)=/_D_(2)` and we know that angle D=65(given)
We have already calculated `D_(1)=45 deg`
`therefore /_D_(2) = 65-45 = 20 therefore /_B_(2)=20`
As the angles of a triangle = 180:`/_C= 180 - 20 -20=140`
Ans: Angle B= 65 deg and Angle C=140 degrees.