A hot solution of potassium persulfate slowly decomposes, giving oxygen as one of the products as;
Calculate the maximum volume of oxygen gas that can be produced at 80C when a solution containing 0.100 mol of potassium persulfate decomposes as shown above.
[At 80 °C 1 mol of oxygen has a volume of 29.0 dm3]
`2K_2S_2O_8:O_2 = 2:1`
Amount of `2K_2S_2O_8` decomposed `= 0.1 mol`
Amount of `O_2` formed `= 0.1/2 = 0.05 mol`
It is given that the volume of 1 mol of `O_2` at 80C is `29dm^3` .
Volume of 0.05 moles of `O_2` at 80C `= 29xx0.05 = 1.45dm^3`
So the maximum volume of `O_2` that can be obtained by decomposing 0.1 mol of `2K_2S_2O_8 ` is `1.45dm^3` .