A hockey player accelerates a puck of 0.167 kg from rest to 50 m/s in 0.0121 sec. Determine the acceleration of the puck and the force applied by the hockey stick

Expert Answers
justaguide eNotes educator| Certified Educator

Force is given by the product of mass and acceleration. A force applied to an object results in a change in its velocity.

Here, the initial velocity of the puck is 0 m/s. When the hockey player strikes the puck and exerts a force on it the velocity increases to 50 m/s in 0.0121 seconds.

The acceleration of the puck is (50 - 0)/0.0121 = 4132.23 m/s^2. The force that has been applied and which results in this is the product 0.167*4132.23 = 690 N.

A force of 690 N applied for 0.0121 seconds increases the velocity of a puck of mass 0.167 kg from rest to 50 m/s.