hi there! my question goes: Gas fireplaces burn methane using oxygen from the air. If 4.00L of methane is burned,predict the volume of oxygen..(cotd)
required for complete combustion.
Please can anyone explain this topic to me? Am really confused and I really need help on the topic. Help will be greatly appreciated!
Methane has a molecular formula given by CH4. The reaction that occurs when it reacts with O2 is CH4 + 2O2 --> CO2 + 2H20.
We can use the Ideal Gas Law, PV= nRT to determine the volume of oxygen required to burn 4.00L of methane. We assume the variables of temperature (T) and pressure (P) are the same when the volume of oxygen is being calculated. So from PV= nRT, we get that V is proportional to n or the volume is proportional to the moles of gas required.
Now the equation of the reaction between methane and oxygen, gives us that 2 moles of oxygen are required for each mole of methane. Also, the volume of the gas required is proportional to the number of moles. Therefore for the complete combustion of 4.00 L of methane we need 2*4.00 = 8.00 L of oxygen.
The required volume of oxygen is 8.00L.
Hope this explanation helped you.