# Hi!Please help me with this problem:I must to demonstrate this function y=x^3/2 + C/x^3 is a solution for this differential equation: dy/dx+3y/x=3x^2

*print*Print*list*Cite

### 1 Answer

Simply insert your `y` in differential equation:

`(dy)/(dy)+3y/x=(3x^2)/(2)-(3C)/(x^4)+((3x^2)/(2)+(3C)/(x^3))/(x)=`

`(3x^6-6C+3x^6+6C)/(2x^4)=(6x^6)/(2x^4)=3x^2`

which is what you were supposed to get.