What is the procedure for the preparation of 1-100 ml of 0.1 M sodium hydroxide standard solution?

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I edited you question to be a little more clear.  In order to prepare any given volume of 0.1 M NaOH solution you just need to multiply the desired volume in liters by 0.1 to get the number of moles of NaOH needed and then multiply again by 40 grams/mole to get the mass of NaOH needed in grams (the molecular weight of NaOH is 40 grams/mole).

For example: if you wanted 100 mL of a 0.1 M NaOH solution:

100 mL*(1 L/1000 mL)=0.1 liters

0.1 L (0.1 mole/L)(40 grams/mole)=0.4 grams NaOH

So you would take 0.4 grams (400 mg) of NaOH and dissolve it in 100 mL of water.

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